document.write( "Question 67023This question is from textbook Beginning Algebra
\n" ); document.write( ": Graph the functions: f(x) = -2x - 5. I am not doing to well with these fuctions, so any help with trying to graph one is greatly appreceated. Thanks \n" ); document.write( "
Algebra.Com's Answer #47656 by Earlsdon(6294)\"\" \"About 
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If you are graphing this by hand (no grahing calculator), the best way to proceed is to first replace the f(x) with y:
\n" ); document.write( "\"y+=+-2x-5\" then make what is called an input/output table.
\n" ); document.write( "You do this by assigning a numerical value to x (start with small values to make the calculations easier) then find the corresponding value of y.
\n" ); document.write( "For a linear function such as this, you need only two points to draw the line.
\n" ); document.write( "So, let's see how this goes!
\n" ); document.write( "\"y+=+-2x-5\" Substitute 0 for x and calculate the y.
\n" ); document.write( "\"y+=+-2%280%29-5\"
\n" ); document.write( "\"y+=+-5\" So here's one point (0, -5) that you can graph on your graph paper once you have drawn the x-axis (horizontal line) and the y-axis (vertical line)
\n" ); document.write( "A second point can be found by letting x = 1.
\n" ); document.write( "\"y+=+-2%281%29-5\"
\n" ); document.write( "\"y+=+-2-5\"
\n" ); document.write( "\"y+=+-7\" Here's the second point (1, -7)
\n" ); document.write( "Plot these two points on your coordinate graph and draw a straight line through them.
\n" ); document.write( "Here's what it should look like when you are done:
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C5%2C-8%2C5%2C-2x-5%29\"
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