document.write( "Question 8600: What are three consecutive odd integers such that the first plus three times the second, minus twice the third is 44? \n" ); document.write( "
Algebra.Com's Answer #4765 by mr_burn(1)\"\" \"About 
You can put this solution on YOUR website!
x= Three consecutive integers
\n" ); document.write( "x+3x-2x=44
\n" ); document.write( "2x=44
\n" ); document.write( "x=22 \r
\n" ); document.write( "\n" ); document.write( "22+3(22)-2(22)=44
\n" ); document.write( "22+66-44=44
\n" ); document.write( "88-44=44
\n" ); document.write( "44=44\r
\n" ); document.write( "\n" ); document.write( "x=first odd integer
\n" ); document.write( "2x=second integer
\n" ); document.write( "3x=third integer\r
\n" ); document.write( "\n" ); document.write( "22=first integer
\n" ); document.write( "44=second integer
\n" ); document.write( "66=third integer\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );