document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782693>Question 782693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a piece of tin, 12 inches on a side, is to have four equal squares cut from its corners, as in the illustration. if the edges are then to be folded up to make a box with a floor area of 64 square inches,mfind the depth of the box </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476496 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the side of square cut\r<BR>\n" );
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document.write( "then side length =<BR>\n" );
document.write( "12-2x\r<BR>\n" );
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document.write( "(12-2x)^2=64\r<BR>\n" );
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document.write( "144-48x+4x^2=64\r<BR>\n" );
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document.write( "4x^2-48x+80=0\r<BR>\n" );
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document.write( "/4<BR>\n" );
document.write( "x^2-12x+20=0<BR>\n" );
document.write( "x^2-10x-2x+20=0<BR>\n" );
document.write( "x(x-10)-2(x-10)=0<BR>\n" );
document.write( "(x-10)(x-2)=0<BR>\n" );
document.write( "x= 10 OR 2\r<BR>\n" );
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document.write( "x cannot be 10<BR>\n" );
document.write( "so depth of box = 2inches\r<BR>\n" );
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document.write( " </SPAN>\n" );
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