document.write( "Question 782716: The perimeter and the area of a rectangle are 48 cm and 140 cm square. Find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #476494 by mananth(16946)\"\" \"About 
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perimeter = 48\r
\n" ); document.write( "\n" ); document.write( "let length = l
\n" ); document.write( "width =w\r
\n" ); document.write( "\n" ); document.write( "2(l+w)=48
\n" ); document.write( "l+w=24................(1)\r
\n" ); document.write( "\n" ); document.write( "area = l*w
\n" ); document.write( "l*w=140
\n" ); document.write( "l=140/w\r
\n" ); document.write( "\n" ); document.write( "substitute l in (1)
\n" ); document.write( "140/w + w = 24\r
\n" ); document.write( "\n" ); document.write( "multiply equation by w\r
\n" ); document.write( "\n" ); document.write( "140+w^2=24w\r
\n" ); document.write( "\n" ); document.write( "w^2-24w+140=0\r
\n" ); document.write( "\n" ); document.write( "w^2-14w-10w+140=0\r
\n" ); document.write( "\n" ); document.write( "w(w-14)-10(w-14)=0
\n" ); document.write( "(w-14)(w-10)=0\r
\n" ); document.write( "\n" ); document.write( "w=10 OR 14\r
\n" ); document.write( "\n" ); document.write( "dimensions are 14cm and 10cm
\n" ); document.write( "
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