document.write( "Question 782643: you invested $24000 in two accounts paying 5% and 9% annual interest, respectively. if the total interest earned for the year was $1400, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #476484 by mananth(16946)\"\" \"About 
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Part I 5.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 9.00% per annum ------------ Amount invested = y
\n" ); document.write( " 24000
\n" ); document.write( "Interest----- 1400.00
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\n" ); document.write( "Part I 5.00% per annum ---x
\n" ); document.write( "Part II 9.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 24000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "5.00% x + 9.00% y= 1400
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5 x + 9 y= 140000.00 --------2
\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
\n" ); document.write( "-5 x -5 y= -120000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 20000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 5000 - x)
\n" ); document.write( "Part I 5.00% $ 19000
\n" ); document.write( "Part II 9.00% $ 5000
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\n" ); document.write( "CHECK
\n" ); document.write( "19000 --------- 5.00% ------- 950.00
\n" ); document.write( "5000 ------------- 9.00% ------- 450.00
\n" ); document.write( "Total -------------------- 1400.00
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\n" ); document.write( "m.ananth@hotmail.ca
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