document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782666>Question 782666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20% copper should be mixed with 400 ounces of an alloy that is 60% copper in order to get an alloy that is 30% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476476 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 20% copper should be mixed with 400 ounces of an alloy that is 60% copper in order to get an alloy that is 30% copper?<BR>\n" );
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document.write( "let x= amount  of 20% copper alloy to be mixed with 400 ounces of 60% copper alloy<BR>\n" );
document.write( "400-x= amount 60% copper alloy to be mixed with 20% copper alloy<BR>\n" );
document.write( "..<BR>\n" );
document.write( "20%x+60%(400-x)=30%*400<BR>\n" );
document.write( ".20x+240-.60x=120<BR>\n" );
document.write( ".40x=120<BR>\n" );
document.write( "x=300<BR>\n" );
document.write( "amount  of 20% copper alloy to be mixed with 400 ounces of 60% copper alloy=300 ounces </SPAN>\n" );
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