document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782511>Question 782511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the angle supplement is 60 degrees more than four times of that of its complement. Find the measure of the angle described </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476413 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of the angle supplement is 60 degrees more than four times of that of its complement<BR>\n" );
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document.write( "angle:: x<BR>\n" );
document.write( "complemet: 90-x<BR>\n" );
document.write( "supplement: 180-x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = 4(90-x)+60<BR>\n" );
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document.write( "180-x = 360 -4x + 60<BR>\n" );
document.write( "3x = 240<BR>\n" );
document.write( "x = 80 degrees (the angle)<BR>\n" );
document.write( "90-x = 10 degrees (the complement)<BR>\n" );
document.write( "180-x = 100 degrees (the supplement)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------------ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );