document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782499>Question 782499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of a freight train is 14 km/h slower than the speed of a passenger train. The freight train travels 330 km in the same time that it takes the passenger train to travel 400 km. Find the speed of each train. Can you show me a simple way to solve this problem with numbered steps? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476405 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> freight train		x	mph			330	miles			<BR>\n" );
document.write( "Passenger train		(x+	14)mph			400	miles			<BR>\n" );
document.write( "										<BR>\n" );
document.write( "t=d/r				400						<BR>\n" );
document.write( "330	/	x	=		/	(	x+		14	)<BR>\n" );
document.write( "Cross multiply				14						<BR>\n" );
document.write( "330	(	x		+14	)	=	400	*	x	<BR>\n" );
document.write( "330	x	+	4620	=	400	x				<BR>\n" );
document.write( "400	x		-330		=	4620				<BR>\n" );
document.write( "70	x	=	4620							<BR>\n" );
document.write( "/	70			mph						<BR>\n" );
document.write( "x	=	66	freight train	mph						<BR>\n" );
document.write( "		80	Passenger train	mph						<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );