document.write( "Question 782462: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables.\r
\n" ); document.write( "\n" ); document.write( "The problem is: A chemist has 15% and 40% solutions of acid available. How may liters of each solution should be mixed to obtain 5 liters of a 20% acid solution?
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Algebra.Com's Answer #476394 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You need two variables.
\n" ); document.write( "x = amount of 15% acid
\n" ); document.write( "y = amount of 40% acid\r
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\n" ); document.write( "\n" ); document.write( "One equation accounts for the concentrations of acid:
\n" ); document.write( "\"%2815x%2B40y%29%2F5=20\"\r
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\n" ); document.write( "\n" ); document.write( "The other equation accounts for the quantities of the acid solutions:
\n" ); document.write( "\"x%2By=5\"
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