document.write( "Question 782314: British sterling silver is a copper-silver alloy that is 7.5% copper by weight. How many grams of pure copper and how many grams of British sterling silver should be used to prepare 190 grams of a copper-silver alloy that is 18% copper by weight? \n" ); document.write( "
Algebra.Com's Answer #476375 by ankor@dixie-net.com(22740)\"\" \"About 
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British sterling silver is a copper-silver alloy that is 7.5% copper by weight.
\n" ); document.write( " How many grams of pure copper and how many grams of British sterling silver should be used to prepare 190 grams of a copper-silver alloy that is 18% copper by weight?
\n" ); document.write( ":
\n" ); document.write( "let x = the amt of pure copper required
\n" ); document.write( "then
\n" ); document.write( "(190-x) = amt of sterling silver
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation
\n" ); document.write( ".075(190-x) + x = .18(190)
\n" ); document.write( "14.25 - .075x + x = 34.2
\n" ); document.write( "1x - .075x = 34.2 - 14.25
\n" ); document.write( ".925x = 19.25
\n" ); document.write( "x = 19.25/.925
\n" ); document.write( "x ~ 21.57 grams of pure copper
\n" ); document.write( "then
\n" ); document.write( "190 - 21.57 = 168.43 grams Br Sterling \n" ); document.write( "
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