document.write( "Question 782276: Chris is 5 years older than jacob. Four years from now chris will be twice as old as jacob. How old is chris now? \n" ); document.write( "
Algebra.Com's Answer #476354 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = Jacob's age now \n" ); document.write( "x + 5 = Chris' age now\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 4 = Jacob's age in 4 years \n" ); document.write( "x + 9 = Chris' age in 4 years {added 4 onto current age}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 9 = 2(x + 4) {in 4 years, Chris will be twice as old as Jacob} \n" ); document.write( "x + 9 = 2x + 8 {used distributive property} \n" ); document.write( "9 = x + 8 {subtracted x from each side} \n" ); document.write( "x = 1 {subtracted 8 from each side} \n" ); document.write( "x + 5 = 6 {substituted 1, in for x, into x + 5}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Chris is 6 now \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |