document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782257>Question 782257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 9% solution of salt should be added to a 19% solution in order to obtain 300 liters of a 15% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476345 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of liters of 9% solution<BR>\n" );
document.write( "300 - x = number of liters of 19% solution\r<BR>\n" );
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document.write( "0.09x + 0.19(300 - x) = 0.15(300) {number of liters times percent equals total solution}<BR>\n" );
document.write( "0.09x + 57 - 0.19x = 45 {used distributive property and multiplied}<BR>\n" );
document.write( "-0.1x + 57 = 45 {combined like terms}<BR>\n" );
document.write( "-0.1x = -12 {subtracted 57 from each side}<BR>\n" );
document.write( "x = 120 liters of 9% solution {divided each side by -0.1}\r<BR>\n" );
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document.write( "120 liters of 9% solution must be added<BR>\n" );
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