document.write( "Question 782217: how many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol? \n" ); document.write( "
Algebra.Com's Answer #476337 by stanbon(75887)\"\" \"About 
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how many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol?
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\n" ); document.write( "Equaton::
\n" ); document.write( "alch + alch = alch
\n" ); document.write( "0.35x + 0.60(40-x) = 0.52(40)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "35x + 60*40 - 0.60x = 52*40
\n" ); document.write( "-25x = -8*40
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\n" ); document.write( "x = (8/5)8
\n" ); document.write( "x = 64/5 = 12 4/5 liters (amt of 35% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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