document.write( "Question 66999This question is from textbook Advanced mathematics
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document.write( ": Find the number that is (4/5) of the way from 1(1/4) to -6(2/3). \n" );
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Algebra.Com's Answer #47633 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Find the number that is (4/5) of the way from 1(1/4) to -6(2/3).\r \n" ); document.write( "\n" ); document.write( "Distance between 1(1/4) and -6(2/3)= \n" ); document.write( "1(1/4)-(-6(2/3))=1(1/4)+6(2/3)= \n" ); document.write( "5/4+20/3 LCM is 12 \n" ); document.write( "5/4=15/12 \n" ); document.write( "20/3=80/12 so we have \n" ); document.write( "(15+80)/12=95/12 \n" ); document.write( "Distance between 1(1/4) and -6(2/3)= 95/12 units\r \n" ); document.write( "\n" ); document.write( "4/5 of 95/12 units =(4/5)(95/12)=95/15=19/3 units \n" ); document.write( "Also, 1/5 of 95/12=19/12 units\r \n" ); document.write( "\n" ); document.write( "We have the distance between 1(1/4) and -6(2/3),now we need to find (4/5) of the way from 1(1/4) towards -6(2/3)which equals:\r \n" ); document.write( "\n" ); document.write( "1(1/4)-19/3= (Note: we are going in the negative direction) \n" ); document.write( "5/4-19/3; LCM is 12 \n" ); document.write( "(15-76)/12=-61/12 ------------------number we are looking for\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "We will go 1/5 of the way from -6(2/3) to 1(1/4) and we are going in the positive direction so we must add 19/12:\r \n" ); document.write( "\n" ); document.write( "-6(2/3)+19/12= \n" ); document.write( "-20/3+19/12= LCM is 12\r \n" ); document.write( "\n" ); document.write( "(-80+19)/12= \n" ); document.write( "-61/12 units -----------------the number we are looking for\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |