document.write( "Question 782199: How do I set this up: For a long distance call, the telephone company charges .35 for each of the first three minutes and .15 for each additional minute. If the cost of a call was $12.30, how many minutes did the call last?
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Algebra.Com's Answer #476318 by josmiceli(19441) $\"\"$ $\"About$

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It went past the 1st 3 minutes so
\n" ); document.write( "you have to add $.35
\n" ); document.write( "In words:
\n" ); document.write( "( cost ) = ( cost for 1st 3 min ) + ( .15 x minutes after that )
\n" ); document.write( "Let $\"+x+\"$ = total minutes minus $\"+3+\"$ minutes
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\n" ); document.write( " $\"+c+=+.35+%2B+.15x+\"$
\n" ); document.write( " $\"+12.3+=+.35+%2B+.15x+\"$
\n" ); document.write( " $\"+.15x+=+11.95+\"$
\n" ); document.write( " $\"+x+=+79.667+\"$
\n" ); document.write( "Add in the 1st $\"+3+\"$ min
\n" ); document.write( " $\"+x+%2B+3+=+82.667+\"$
\n" ); document.write( " $\"+82.667+-+60+=+22.667+\"$ min
\n" ); document.write( " $\"+.667%2A60+=+40+\"$ sec
\n" ); document.write( "The call lasted 1 hour 22 minutes and 40 seconds \n" ); document.write( "

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