document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66981>Question 66981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following equation.  Be sure to check your answer by plugging your answer back into the equation.  \r<BR>\n" );
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document.write( "(sqrt2y+7)+4=y\r<BR>\n" );
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document.write( "I have gotten to the quadratic equation of y^2-10y+9=0, but I am stuck at that point. Can someone please lend me a hand here. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47630 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(2y+7)+4=y <BR>\n" );
document.write( "sqrt(2y+7)=y-4<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "2y+7=y^2-8y+16<BR>\n" );
document.write( "y^2-10y+9=0<BR>\n" );
document.write( "(y-9)(y-1)=0<BR>\n" );
document.write( "y=9 or y=1<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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