document.write( "Question 782074: A cylinder with a top and bottom has height 15 in. and has a total surface area that is twice the area of a circle whose radius is 6 in. more than the radius of the cylinder. What is the radius of the cylinder? \n" ); document.write( "
Algebra.Com's Answer #476282 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A cylinder with a top and bottom has height 15 in. and has a total surface area that is twice the area of a circle whose radius is 6 in. more than the radius of the cylinder. What is the radius of the cylinder?\r \n" ); document.write( "\n" ); document.write( "radius of cylinder=r\r \n" ); document.write( "\n" ); document.write( "radius of circle =r+6\r \n" ); document.write( "\n" ); document.write( "Area of circle= pi * (r+6)^2\r \n" ); document.write( "\n" ); document.write( "2 times area = 2pi(r+6)^2\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "Area of cylinder\r \n" ); document.write( "\n" ); document.write( "2pir^2+2pirh\r \n" ); document.write( "\n" ); document.write( "2pir^2+2pir*15\r \n" ); document.write( "\n" ); document.write( "2pir^2+30pir\r \n" ); document.write( "\n" ); document.write( "equate both\r \n" ); document.write( "\n" ); document.write( "2pir^2+30pir=2pi(r+6)^2 \n" ); document.write( "2pir(r+15)=2pi(r+6)^2 \n" ); document.write( "r(r+15)=(r+6)^2\r \n" ); document.write( "\n" ); document.write( "r^2+15r=r^2+12r+36\r \n" ); document.write( "\n" ); document.write( "15r-12r=36\r \n" ); document.write( "\n" ); document.write( "3r=36 \n" ); document.write( "/3 \n" ); document.write( "r=12\r \n" ); document.write( "\n" ); document.write( "radius = 12 inch\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |