document.write( "Question 782074: A cylinder with a top and bottom has height 15 in. and has a total surface area that is twice the area of a circle whose radius is 6 in. more than the radius of the cylinder. What is the radius of the cylinder? \n" ); document.write( "
Algebra.Com's Answer #476282 by mananth(16946)\"\" \"About 
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A cylinder with a top and bottom has height 15 in. and has a total surface area that is twice the area of a circle whose radius is 6 in. more than the radius of the cylinder. What is the radius of the cylinder?\r
\n" ); document.write( "\n" ); document.write( "radius of cylinder=r\r
\n" ); document.write( "\n" ); document.write( "radius of circle =r+6\r
\n" ); document.write( "\n" ); document.write( "Area of circle= pi * (r+6)^2\r
\n" ); document.write( "\n" ); document.write( "2 times area = 2pi(r+6)^2\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "Area of cylinder\r
\n" ); document.write( "\n" ); document.write( "2pir^2+2pirh\r
\n" ); document.write( "\n" ); document.write( "2pir^2+2pir*15\r
\n" ); document.write( "\n" ); document.write( "2pir^2+30pir\r
\n" ); document.write( "\n" ); document.write( "equate both\r
\n" ); document.write( "\n" ); document.write( "2pir^2+30pir=2pi(r+6)^2
\n" ); document.write( "2pir(r+15)=2pi(r+6)^2
\n" ); document.write( "r(r+15)=(r+6)^2\r
\n" ); document.write( "\n" ); document.write( "r^2+15r=r^2+12r+36\r
\n" ); document.write( "\n" ); document.write( "15r-12r=36\r
\n" ); document.write( "\n" ); document.write( "3r=36
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\n" ); document.write( "r=12\r
\n" ); document.write( "\n" ); document.write( "radius = 12 inch\r
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