document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66932>Question 66932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this: i am not sure what to do.<BR>\n" );
document.write( "(1/3)-(2/x-2)+(1/x+1)\r<BR>\n" );
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document.write( "Thank you Chelsie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47628 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/3)-(2/x-2)+(1/x+1) <BR>\n" );
document.write( "--------<BR>\n" );
document.write( "The least common denominator (lcd) is 3(x-2)(x+1)<BR>\n" );
document.write( "Rewrite each fraction with the lcd as its denominator.<BR>\n" );
document.write( "[(x-2)(x+1)/lcd] - [2*3(x+1)] + [3(x-2)]<BR>\n" );
document.write( "Combine the numerators over the lcd, as follows:<BR>\n" );
document.write( "[(x^2-x+1)-6x-6+3x-6]/lcd<BR>\n" );
document.write( "[x^2-4x-11]/[3(x-2)(x+1)]<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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