document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782109>Question 782109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two boys A and B are at two diametrically opposite points on a circle. At one instant the two start running on the circle; A anticlockwise with constant speed v and B clockwise with constant speed 2v. In 2 minutes, they pass each other for the first time. How much later will they pass each other for the second time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476272 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A speed = v\r<BR>\n" );
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document.write( "B speed = 2v\r<BR>\n" );
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document.write( "Time to meet = 2 minutes\r<BR>\n" );
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document.write( "d= pi r ( distance they have to run to meet)\r<BR>\n" );
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document.write( "they are running towards each other.<BR>\n" );
document.write( "(2v+v)\r<BR>\n" );
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document.write( "speed = 3v\r<BR>\n" );
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document.write( "d=rt\r<BR>\n" );
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document.write( "pi*r = 3v*2\r<BR>\n" );
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document.write( "r= 6v/pi\r<BR>\n" );
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document.write( "circumference = 2* pi*r\r<BR>\n" );
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document.write( "=2*pi*(6v/pi)\r<BR>\n" );
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document.write( "=12v<BR>\n" );
document.write( "...\r<BR>\n" );
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document.write( "Now distance to travel to meet = 12v\r<BR>\n" );
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document.write( "speed = 3v\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "t= 12v/3v \r<BR>\n" );
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document.write( "t= 4 minutes\r<BR>\n" );
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document.write( " </SPAN>\n" );
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