document.write( "Question 782046: Complete the square to re-write the equation into standard form.
\n" ); document.write( "5x^2+20x+2y^2-28y=2
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Algebra.Com's Answer #476255 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Take out a factor for the x's and another for the y's.\r
\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B20x%2B2y%5E2-28y=2\"
\n" ); document.write( "\"5%28x%5E2%2B4x%29%2B2%28y%5E2-14y%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "The square term for the x's is \"%284%2F2%29%5E2=4\" and the one for the y's is \"%28-14%2F2%29%5E2=49\".\r
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\n" ); document.write( "\n" ); document.write( "\"5%28x%5E2%2B4x%2B4%29%2B2%28y%5E2-14y%2B49%29=2%2B5%2A4%2B2%2A49\"
\n" ); document.write( "Notice very carefully how we must use the factorization to properly add the same quantities to BOTH sides of the equation.\r
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\n" ); document.write( "\n" ); document.write( "Factorize on the left and simplify on the right:
\n" ); document.write( "\"5%28x%2B2%29%5E2%2B2%28y-7%29%5E2=120\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 120:
\n" ); document.write( "\"%28x%2B2%29%5E2%2F24%2B%28y-7%29%5E2%2F60=1\"
\n" ); document.write( "You might want further refinement for the a^2=60 and your b^2=24
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