document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=782054>Question 782054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a store mixes red fescue worth $10 per pound and ryegrass worth $13 per pound. THe mixture is to sell for $12 per pound. Find how much of each should be used to make a 264 pound mixture </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476248 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = pounds of $10 per pound red fescue<BR>\n" );
document.write( "264 - x = pounds of $13 per pound ryegrass\r<BR>\n" );
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document.write( "10x + 13(264 - x) = 12(264) {price multiplied by number of pounds equals total value}<BR>\n" );
document.write( "10x + 3432 - 13x = 3168 {used distributive property and multiplied}<BR>\n" );
document.write( "-3x + 3432 = 3168 {combined like terms}<BR>\n" );
document.write( "-3x = -264 {subtracted 3432 from each side}<BR>\n" );
document.write( "x = 88 pounds of $10/pound red fescue {divided each side by -3}<BR>\n" );
document.write( "264 - x = 176 pounds of $13 per pound ryegrass {substituted 88, in for x, into 264 - x}\r<BR>\n" );
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document.write( "88 pounds of $10 per pound red fescue<BR>\n" );
document.write( "176 pounds of $13 per pound ryegrass<BR>\n" );
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