document.write( "Question 8600: What are three consecutive odd integers such that the first plus three times the second, minus twice the third is 44? \n" ); document.write( "

Algebra.Com's Answer #4762 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x= first integer
\n" ); document.write( "x+2 = second integer
\n" ); document.write( "x+4 = third integer\r
\n" ); document.write( "\n" ); document.write( "Now just do what the sentence says to do:
\n" ); document.write( "First + 3(Second) - 2(Third) = 44
\n" ); document.write( "x + 3(x+2) - 2(x+4) = 44
\n" ); document.write( "x + 3x + 6 - 2x - 8 = 44
\n" ); document.write( "2x -2 = 44
\n" ); document.write( "2x = 46
\n" ); document.write( "x=23 First
\n" ); document.write( "x+2 = 25 Second
\n" ); document.write( "x+4 = 27 Third\r
\n" ); document.write( "\n" ); document.write( "Check: Again, do what it says to do!
\n" ); document.write( "23 + 3(25) - 2(27)
\n" ); document.write( "23 + 75 - 54
\n" ); document.write( "98 - 54
\n" ); document.write( "44\r
\n" ); document.write( "\n" ); document.write( "It checks!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( " \n" ); document.write( "

\n" );