document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66963>Question 66963</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132191407/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> what is the value of X?\r<BR>\n" );
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document.write( "5x-(2x+2)=x+(3x-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47619 by </B><A HREF=/tutors/aboutme.mpl?userid=bam878s><B>bam878s(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bam878s><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the beginning we have<BR>\n" );
document.write( "5x-(2x+2) = x+(3x-5)\r<BR>\n" );
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document.write( "5x-2x-2 = x+3x-5  \r<BR>\n" );
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document.write( "Now that we got rid of those horrible parentheses we can do something with this equation.\r<BR>\n" );
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document.write( "Let's start by adding two to both sides:\r<BR>\n" );
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document.write( "(5x-2x-2)+2 = (x+3x-5)+2\r<BR>\n" );
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document.write( "to get\r<BR>\n" );
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document.write( "5x-2x-2+2 = x+3x-5+2<BR>\n" );
document.write( "5x-2x = x+3x-3\r<BR>\n" );
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document.write( "Now let's add the \"x\" terms\r<BR>\n" );
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document.write( "5x-2x = x+3x-3<BR>\n" );
document.write( "3x = 4x-3\r<BR>\n" );
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document.write( "Now let's subtract 3x to both sides\r<BR>\n" );
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document.write( "3x-3x = (4x-3)-3x<BR>\n" );
document.write( "0 = 4x-3-3x<BR>\n" );
document.write( "0 = x-3\r<BR>\n" );
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document.write( "Now simply add 3 to both sides\r<BR>\n" );
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document.write( "0+3 = (x-3)+3<BR>\n" );
document.write( "3 = x-3+3<BR>\n" );
document.write( "3 = x-0<BR>\n" );
document.write( "3=x.  You can see by plugging 3 into the original equation that 3 is the correct answer.\r<BR>\n" );
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document.write( "The key to problems like these are to utilize the following equalities<BR>\n" );
document.write( "For any numbers a,b, and c, we have<BR>\n" );
document.write( "a(b+c) = ab+ac<BR>\n" );
document.write( "(a+b)c= ab+ac.\r<BR>\n" );
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document.write( "These helped alot when we added \"x\" terms.  For instance the fact that 2x+6x=8x may not make since to someone first starting out with algebra.  But, to look at it another way and utilizing the above formulas we see\r<BR>\n" );
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document.write( "2x+6x = (2+6)x = 8x\r<BR>\n" );
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document.write( "When we had 5x-(2x+2), let's first \"drop\" the 5x and look at just -(2x+2).  Well, this is just -1(2x+2).  So, using the above formulas, we have -2x-2 when we multiply out the (-1).  That is how I got 5x-(2x+2) = 5x-2x-2.  \r<BR>\n" );
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document.write( "I hope this helps!<BR>\n" );
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