document.write( "Question 781909: Diophantus's youth lasted one sixth of his life. He grew a beard after one twelfth more. After one seventh more of his life, he married. 5 years later, he and his wife had a son. The son lived exactly one half as long as his father, and Diophantus died four years after his son. \r
\n" );
document.write( "\n" );
document.write( "How many years did Diophantus live? \n" );
document.write( "
Algebra.Com's Answer #476155 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Diophantus's youth lasted one sixth of his life. \n" ); document.write( " He grew a beard after one twelfth more. \n" ); document.write( " After one seventh more of his life, he married. \n" ); document.write( " 5 years later, he and his wife had a son. \n" ); document.write( " The son lived exactly one half as long as his father, and Diophantus died four years after his son.\r \n" ); document.write( "\n" ); document.write( "How many years did Diophantus live?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x = his final age \n" ); document.write( ": \n" ); document.write( "a lengthy but simple equation \n" ); document.write( "Final age = child + youth + bach + marriage + son's age + 4 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Common denominator of 12*7 = 84 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "x = 9 * \n" ); document.write( ": \n" ); document.write( "x = 84 is his final age \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "14 + 7 + 12 + 5 + 42 + 4 = 84 \n" ); document.write( " |