document.write( "Question 781211: length of a dog run is 9 feet more than twice the width and the perimeter is 34 feet, what is the length and width \n" ); document.write( "
Algebra.Com's Answer #476141 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! 1) l=2w+9 \n" ); document.write( "2) 34=2(l+w)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "17=l+w \n" ); document.write( "17=2w+9+w \n" ); document.write( "17-9=3w \n" ); document.write( "w=8/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so \n" ); document.write( "l= \n" ); document.write( "2*8/3+9= \n" ); document.write( "16/3+27/3= \n" ); document.write( "43/3 \n" ); document.write( " \n" ); document.write( " |