document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=781192>Question 781192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a certain number less than 100. The sum of the digits is 7 and the product of the digits is 6. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #476139 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=476139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we describe the number as 100=xy so that x is in the 10's place and y in the ones place, then:\r<BR>\n" );
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document.write( "1) x+y=7<BR>\n" );
document.write( "2) xy=6\r<BR>\n" );
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document.write( "x=6/y\r<BR>\n" );
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document.write( "6/y+y=7<BR>\n" );
document.write( "6+y^2=7y<BR>\n" );
document.write( "y^2-7y+6=0<BR>\n" );
document.write( "(y-6)(y-1)=0\r<BR>\n" );
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document.write( "y=6 or y=1\r<BR>\n" );
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document.write( "there are two numbers possible: 16 and 61 </SPAN>\n" );
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