document.write( "Question 781743: Please help me solve this equation: \"tan+x=+-+sqrt%28+3+%29+\". \n" ); document.write( "
Algebra.Com's Answer #476111 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
tan x= - sqrt( 3 )
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\n" ); document.write( "Draw a 30-60 degree right triangle.
\n" ); document.write( "Label the angles so you see where 30 degrees is
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\n" ); document.write( "Let the side opposite the 30 degree angle be 1
\n" ); document.write( "Then the hypotenuse is 2
\n" ); document.write( "And the side opposite the 60 degree angle is sqrt(3)
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\n" ); document.write( "Notice that tan(60) = sqrt(3)/1 = sqrt(3)
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\n" ); document.write( "So 60 degrees is the reference angle.
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\n" ); document.write( "Then x = arctan(-sqrt(3)) is either 180-60 = 120 degrees
\n" ); document.write( "or x = arctan(-sqrt(3))is 360-60 = 300 degrees.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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