document.write( "Question 781803: Two cars enter the Florida Turnpike at commercial Boulevard at 8 AM, each heading for Wildwood. One car's average speed is 10 mph more than the other's. The faster car arrives at Wildwood at 11 AM, 1/2 hour before the other car. What is the average speed of each car? How far did each travel? \n" ); document.write( "
Algebra.Com's Answer #476106 by stanbon(75887)\"\" \"About 
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Two cars enter the Florida Turnpike at commercial Boulevard at 8 AM, each heading for Wildwood. One car's average speed is 10 mph more than the other's. The faster car arrives at Wildwood at 11 AM, 1/2 hour before the other car. What is the average speed of each car? How far did each travel?
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\n" ); document.write( "Faster Car DATA:
\n" ); document.write( "rate = x + 10 mph ; time = 3 hrs ; distance = 3x+30 miles
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\n" ); document.write( "Slower Car DATA:
\n" ); document.write( "rate = x mph ; time = 3.5 hrs ; distance = 3.5x miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "3.5x = 3x+30
\n" ); document.write( "(1/2)x = 30
\n" ); document.write( "x = 60 mph (slower car rate)
\n" ); document.write( "x+10 = 70 mph (faster car rate)
\n" ); document.write( "-----
\n" ); document.write( "Faster car distance = 3x+30 = 180 + 30 = 210 miles
\n" ); document.write( "Slower car distance: = 3.5*60 = 210 miles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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