document.write( "Question 781800: Caso de factor común por agrupación de términos. Factorizar:\r
\n" ); document.write( "\n" ); document.write( "b. 6x – 6y – by + bx\r
\n" ); document.write( "\n" ); document.write( "c. 8m3 – 2m2 – 2mn + 8m2n
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Algebra.Com's Answer #476105 by stanbon(75887)\"\" \"About 
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b. 6x – 6y – by + bx
\n" ); document.write( "= 6(x-y)-b(y-x)
\n" ); document.write( "= 6(x-y)+b(x-y)
\n" ); document.write( "= (x-y)(6+b)
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\n" ); document.write( "c. 8m3 – 2m2 – 2mn + 8m2n
\n" ); document.write( "Rearrange:
\n" ); document.write( "8m^3+8m^2n - 2m^2-2mn
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\n" ); document.write( "= 8m^2(m+n)-2m(m+n)
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\n" ); document.write( "= (m+n)(8m^2-2m)
\n" ); document.write( "= 2(m+n)(4m^2-m)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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