document.write( "Question 781798: Foil method question
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Algebra.Com's Answer #476104 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "two numbers that you can add to get \"106\" are \"53\" and \"53\" (when you factor \"106\" you get \"2\" and \"53\"), \r
\n" ); document.write( "\n" ); document.write( "but, there is no number that you can multiply by \"53\" to get \"480\"; so, you need to complete the square this way:\r
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=1+x%5E2-106+x%2B480\" Start with the given equation
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\n" ); document.write( " \"y-480=1+x%5E2-106+x\" Subtract \"480\" from both sides
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\n" ); document.write( " \"y-480=1%28x%5E2-106x%29\" Factor out the leading coefficient \"1\"
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\n" ); document.write( " Take half of the x coefficient \"-106\" to get \"-53\" (ie \"%281%2F2%29%28-106%29=-53\").
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\n" ); document.write( " Now square \"-53\" to get \"2809\" (ie \"%28-53%29%5E2=%28-53%29%28-53%29=2809\")
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\n" ); document.write( " \"y-480=1%28x%5E2-106x%2B2809-2809%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"2809\" does not change the equation
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\n" ); document.write( " \"y-480=1%28%28x-53%29%5E2-2809%29\" Now factor \"x%5E2-106x%2B2809\" to get \"%28x-53%29%5E2\"
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\n" ); document.write( " \"y-480=1%28x-53%29%5E2-1%282809%29\" Distribute
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\n" ); document.write( " \"y-480=1%28x-53%29%5E2-2809\" Multiply
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\n" ); document.write( " \"y=1%28x-53%29%5E2-2809%2B480\" Now add \"480\" to both sides to isolate y
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\n" ); document.write( " \"y=1%28x-53%29%5E2-2329\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=1\", \"h=53\", and \"k=-2329\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=1x%5E2-106x%2B480\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1x%5E2-106x%2B480%29\" Graph of \"y=1x%5E2-106x%2B480\". Notice how the vertex is (\"53\",\"-2329\").
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\n" ); document.write( " Notice if we graph the final equation \"y=1%28x-53%29%5E2-2329\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%28x-53%29%5E2-2329%29\" Graph of \"y=1%28x-53%29%5E2-2329\". Notice how the vertex is also (\"53\",\"-2329\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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