document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66974>Question 66974</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh>0-534-49449-8</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> how would you rationalize the denominator for sqrt 3x/sqrt x- sqrt 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47609 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rationalize the denominator for sqrt 3x/sqrt x- sqrt 3<BR>\n" );
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document.write( "Multiply numerator and denominator by (sqrtx+sqrt3) to get:\r<BR>\n" );
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document.write( "=[3x(sqrtx+sqrt3)]/[x-3]<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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