document.write( "Question 781647: Patrice, by himself, can paint a house in 10 hours. If he hires April to help, they can do the same job together in 6 hours. If he lets April work alone, how long will it take her to paint the same house? \n" ); document.write( "
Algebra.Com's Answer #476048 by josgarithmetic(39618)\"\" \"About 
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Patrice rate is 1/10 jobs per hour
\n" ); document.write( "April AND Patrice Together rate is 1/6 jobs per hour.\r
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\n" ); document.write( "\n" ); document.write( "If assign C = 1/6, the Combined rate, and P = 1/10, Patrice's rate, then A is an unknown rate for April, then:
\n" ); document.write( "\"A%2BP=C\"
\n" ); document.write( "\"A%2B1%2F10=1%2F6\"
\n" ); document.write( "\"A=1%2F6-1%2F10\"
\n" ); document.write( "\"A=10%2F60-6%2F60\"
\n" ); document.write( "\"A=4%2F60\"
\n" ); document.write( "\"A=1%2F15\"-----unit is houses per hour.
\n" ); document.write( "This means, April paints the house by herself in 15 hours.
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