document.write( "Question 781598: Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #475984 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How old are they now? \n" ); document.write( "-------- \n" ); document.write( "Equations: \n" ); document.write( "j = 4L \n" ); document.write( "j+6 + L+6 = 67 \n" ); document.write( "====== \n" ); document.write( "Substitute for \"j\" and solve for \"L\":: \n" ); document.write( "4L + 6 + L + 6 = 67 \n" ); document.write( "5L = 55 \n" ); document.write( "Lacy = 11 yrs (her age now) \n" ); document.write( "----- \n" ); document.write( "Jack = 4L = 44 yrs (his age now) \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |