document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=781586>Question 781586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble solving for this rational equation: 2x-1/3 is > or = to x+1/4+(x/12) If you could help me solve it that would be great. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475978 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-1/3 is > or = to x+1/4+(x/12) <BR>\n" );
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document.write( "2x -(1/3) >= x + (1/4) + (x/12)<BR>\n" );
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document.write( "Multiply thru by 12 to get:<BR>\n" );
document.write( "24x -4 >= 12x + 3 + x<BR>\n" );
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document.write( "11x >= 7<BR>\n" );
document.write( "x >= 7/11<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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