document.write( "Question 781543: How any milliliters of 15% acid should be mixed with 150 milliliters of 40% acid to make 35 % mixture solution\r
\n" );
document.write( "\n" );
document.write( "A: write an equation\r
\n" );
document.write( "\n" );
document.write( "B: solve for x \n" );
document.write( "
Algebra.Com's Answer #475961 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How any milliliters of 15% acid should be mixed with 150 milliliters of 40% acid to make 35 % mixture solution \n" ); document.write( "-------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.40*150 + 0.15x = 0.35(150+x) \n" ); document.write( "------- \n" ); document.write( "40*150 + 15x = 35*150 + 35x \n" ); document.write( "------ \n" ); document.write( "5*150 = 30x \n" ); document.write( "x = 5*5 = 25 ml (amt. of 15% solution needed) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "A: write an equation \n" ); document.write( "B: solve for x \n" ); document.write( " \n" ); document.write( " |