document.write( "Question 781543: How any milliliters of 15% acid should be mixed with 150 milliliters of 40% acid to make 35 % mixture solution\r
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Algebra.Com's Answer #475961 by stanbon(75887)\"\" \"About 
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How any milliliters of 15% acid should be mixed with 150 milliliters of 40% acid to make 35 % mixture solution
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.40*150 + 0.15x = 0.35(150+x)
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\n" ); document.write( "40*150 + 15x = 35*150 + 35x
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\n" ); document.write( "5*150 = 30x
\n" ); document.write( "x = 5*5 = 25 ml (amt. of 15% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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