document.write( "Question 781549: 5x+15y=35
\n" ); document.write( "2x+8y=18 using substitution method
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Algebra.Com's Answer #475950 by rajarn_shahi456(1)\"\" \"About 
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5x+15y=35
\n" ); document.write( "2x+8y=18 using substitution method
\n" ); document.write( "the solution of this equation is given below
\n" ); document.write( "5x+15y=35
\n" ); document.write( "5x=35-15y
\n" ); document.write( "x=(35-15y)/5........(i)
\n" ); document.write( "Now putting the value of equation (i) in equation 2nd
\n" ); document.write( "2((35-15y)/5))+8y=18
\n" ); document.write( "((70-30y)/5))+8y=18
\n" ); document.write( "(70-30y+40y)/5=18
\n" ); document.write( "70+5y=90
\n" ); document.write( "5y=20
\n" ); document.write( " y=4.
\n" ); document.write( "Now puttiing the value of y in equation (i) we get
\n" ); document.write( "x=(35-15y)/5
\n" ); document.write( "x=(35-15*4)/5
\n" ); document.write( "x=-25/5
\n" ); document.write( "x=-5
\n" ); document.write( "there fore x=-5 and y=4 ans.....
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