document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=779603>Question 779603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	A supermarket manager has determined that the amount of time customers spend in the supermarket is approximately normally distributed with a mean of 45 minutes and a standard deviation of 6 minutes. Find the probability that:<BR>\n" );
document.write( "a.	A customer spends less than 48 minutes in the supermarket(3pts)\r<BR>\n" );
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document.write( "b.	Customer spends between 39 and 43 minutes in the supermarket(3pts)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475908 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)<BR>\n" );
document.write( "P(x < 48)=<BR>\n" );
document.write( "P(z < (48-45)/6)=<BR>\n" );
document.write( "P(z < 0.5)=0.6914\r<BR>\n" );
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document.write( "b)<BR>\n" );
document.write( "P(39 < x < 43)=<BR>\n" );
document.write( "P((39-45)/6 < z < (43-45)/6)=<BR>\n" );
document.write( "P(-1 < z < -1/3)=0.2108 </SPAN>\n" );
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