document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=781389>Question 781389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> OUT OF 8 LADIES AND 7 GENTS, 3 LADIES AND 4 GENTS ARE SELECTED FOR A COMMITTEE. PROVIDED THAT MRS. X WILL NOT JOIN COMMITTEE IF MR. X JOINS THE COMMITTEE.<BR>\n" );
document.write( "THEN IN HOW MANY WAYS THE SELECTION IS POSSIBLE ???  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475898 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  8C3 * 7C4 = 1960 combinations if there were no Mr & Mrs x problems.<BR>\n" );
document.write( "But there are! 4/7 of the time Mr x will be selected and 3/8 of that time Mrs x will also be selected. <BR>\n" );
document.write( "4/7 * 3/8 = 12/56 = 3/14 of the time there will be the x problem. 11/14 of the time no problem. 11/14 * 1960 = 1540.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );