document.write( "Question 781227: mulder and scully are driving to Georgia to investigate \"big blue\" a giant reptile reported in one of the local lake. mulder leaves the office at 8:30 am averaging 65mph. scully leaves the office at 9:00am following the same path and averaging 68mph. at what time will scully catch up with mulder \n" ); document.write( "
Algebra.Com's Answer #475874 by ankor@dixie-net.com(22740)\"\" \"About 
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mulder leaves the office at 8:30 am averaging 65mph.
\n" ); document.write( " scully leaves the office at 9:00am following the same path and averaging 68mph. at what time will scully catch up with mulder
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\n" ); document.write( "let t = S's travel time
\n" ); document.write( "then
\n" ); document.write( "(t+.5) = M's travel time
\n" ); document.write( ":
\n" ); document.write( "When S catches M, they will have traveled he same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "68t = 65(t+.5)
\n" ); document.write( "68t = 65t + 32.5
\n" ); document.write( "68t - 65t = 32.5
\n" ); document.write( "3t = 32.5
\n" ); document.write( "t = 32.5/3
\n" ); document.write( "t = 10.833 hrs fro S to catch M
\n" ); document.write( ":
\n" ); document.write( "10.833 hrs = 10 + .8333(60) 10 hrs 50 min
\n" ); document.write( "From 9 AM that would be 7:50 PM, right?
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\n" ); document.write( "We can confirm this by finding the dist of each, (should be the same)
\n" ); document.write( "68 * 10.83 ~ 736 mi
\n" ); document.write( "65(10.83 + .5) ~ 736 mi \n" ); document.write( "
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