document.write( "Question 781173: I am trying to find three consecutive numbers that will equal 170. I have already tried these numbers: 55 56 57 that equals 168 so then I tried to use these numbers: 56 57 58 but it equals 171. \n" ); document.write( "
Algebra.Com's Answer #475807 by josgarithmetic(39618)\"\" \"About 
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Try to think about the qualities of these numbers.\r
\n" ); document.write( "\n" ); document.write( "Any three consecutive numbers, assuming integers, would be as odd, even, odd; or even, odd, even.\r
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\n" ); document.write( "\n" ); document.write( "The sums would be as:\r
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\n" ); document.write( "\n" ); document.write( "odd+even+odd=odd+odd+even=(odd+odd)+even=even+even.
\n" ); document.write( "This result must be EVEN.\r
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\n" ); document.write( "\n" ); document.write( "even+odd+even=(even+even)+odd=even+odd=odd.
\n" ); document.write( "This result must be ODD. \r
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\n" ); document.write( "\n" ); document.write( "The question description might be expected to be no trouble.
\n" ); document.write( "Three consecutive numbers, n, n+1, n+2.
\n" ); document.write( "Sum must be equated to 170 according to given:
\n" ); document.write( "n+n+1+n+2=170
\n" ); document.write( "3n+3=170, and obviouslly this is NOT a product of three and any integer.
\n" ); document.write( "3n=170-3
\n" ); document.write( "3n=167, and neither is this product.\r
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\n" ); document.write( "\n" ); document.write( "For consecutive numbers, they MUST be integers at the very broadest. NO SOLUTION. \n" ); document.write( "
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