document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=781168>Question 781168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A goldsmith mixed 30 g of a 40% gold alloy with 60 g of a 25% gold alloy. What is the percent concentration of the resulting alloy? (Round your answer to the nearest percent.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475805 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Percent of alloy is (Component of interest)/(Total mixture), and then multiplied by 100.\r<BR>\n" );
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document.write( "Amount of gold = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%2A40%2B60%2A25 ALIGN=MIDDLE  ALT=\"30%2A40%2B60%2A25\"   DISABLED_style= \"max-width:90%; height:auto;\" > which already represents that factor of 100.<BR>\n" );
document.write( "Amount of mixture, alloy = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%2B60 ALIGN=MIDDLE  ALT=\"30%2B60\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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