document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=781151>Question 781151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I solve for this rational equation: x-3/3 is less than or equal to 2+(x/2)<BR>\n" );
document.write( "I tried working it like this but I am not too sure it is right.<BR>\n" );
document.write( "6*(x-3/3) is less than or equal to 6*(2+(x/2))<BR>\n" );
document.write( "6x-18 is less than/equal to 12+6x<BR>\n" );
document.write( "-18 is less than or equal to 12<BR>\n" );
document.write( "Im just not sure if that's right. If you could help me that would be great because I am also struggling with another similar problem so I would appreciate it if you could help me out. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475801 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  x-3/3 is less than or equal to 2+(x/2)<BR>\n" );
document.write( "multiply by 6<BR>\n" );
document.write( "6x -18/3 < or = 12 +6x/2<BR>\n" );
document.write( "6x -6 < or = 12 +3x<BR>\n" );
document.write( "add 6 to both sides<BR>\n" );
document.write( "6x < or = 18 +3x<BR>\n" );
document.write( "subtract 3x from both sides<BR>\n" );
document.write( "3x < or = 18<BR>\n" );
document.write( "x < or = 6<BR>\n" );
document.write( "notice that we did not have to multiply or divide by a negative number so the direction of the < stayed the same<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );