document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66880>Question 66880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/4x-1/3x+=5/6x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47571 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/4x-1/3x+=5/6x-5  LCM is 24x  so we'll first multiply every term by 24x\r<BR>\n" );
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document.write( "(24x/4x)(3)-24x/3x=(24x/6x)(5)-5(24x)  simplify\r<BR>\n" );
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document.write( "18-8=20-120x  subtract 20 from both sides<BR>\n" );
document.write( "18-8-20=20-20-120x   collect like terms\r<BR>\n" );
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document.write( "-10=-120x  divide both sides by -120\r<BR>\n" );
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document.write( "x=10/120=1/12\r<BR>\n" );
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document.write( "ck\r<BR>\n" );
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document.write( "3/4(1/12)-1/3(1/12)=5/6(1/12)-5\r<BR>\n" );
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document.write( "9-4=10-5<BR>\n" );
document.write( "5=5\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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