document.write( "Question 780830: Ehmjie bought three times as many burgers as chocolate bars. Each burger costs Php30 and each chocolate bar is Php55 more than each burger. If she spent Php700 in all, how many chocolate bars did she buy? \n" ); document.write( "
Algebra.Com's Answer #475701 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Linear system of equations.\r \n" ); document.write( "\n" ); document.write( "Let x = count of burgers \n" ); document.write( "Let y = count of chocolate bars \n" ); document.write( "Given information makes \n" ); document.write( "cost for the burgers, \n" ); document.write( "cost for the chocolate bars, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Actual cost spent was 700 Php, so this must be the sum of the costs of each product. \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Easiest way to handle the system is use the formula for x to substitute into the total cost 700 equation, and solve for the y value. Return again to the formula for x and use the y value to compute x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------Skipping the steps from there, and keeping results as rational numbers,------------- \n" ); document.write( " \n" ); document.write( " |