document.write( "Question 780850: If (log x)/2=(log y)/3=(log z)/5. then yz in term of x is \n" ); document.write( "
Algebra.Com's Answer #475700 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
remember that a*log(b) = \"log%28%28b%5Ea%29%29\"

log(x)


\n" ); document.write( "log(x) = 2/3 * log(y) = log(y^(2/3)).


\n" ); document.write( "Remember if log(a) = log(b) then a=b


\n" ); document.write( "x = y^(2/3)


\n" ); document.write( "Similarly x = z^(2/5)


\n" ); document.write( "y^(2/3) * y^(1/3) = y. y^(1/3) = sqrt(x) so y = x*sqrt(x)


\n" ); document.write( "z^(2/5) * z^(2/5) * z^(1/5) = z. z^(2/5) = x, so that's x*x*sqrt(x) = x^2 * sqrt(x).


\n" ); document.write( "yz = \"x%2Asqrt%28x%29+%2A+x%5E2+%2A+sqrt%28x%29+=+x%5E4\"
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