document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66898>Question 66898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the simple interest formula to find the principal if the\r<BR>\n" );
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document.write( "total interest earned was $150 and the rate of interest was 4% for 2 years.\r<BR>\n" );
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document.write( "Dollars=P Interest=I Rate of interest=r Time calculated in years=t. Simple interest formula is I=Prt.\r<BR>\n" );
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document.write( "Keeping this forumla in mind and the information provided it would seem that 150=P x 0.04 x 2, next step looks  like 150=P x 0.08, to get P we will divide 150 by 0.08. This works out to be 1875. So the principal is $1875.<BR>\n" );
document.write( "did i do this right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47570 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the simple interest formula to find the principal if the<BR>\n" );
document.write( "total interest earned was $150 and the rate of interest was 4% for 2 years.<BR>\n" );
document.write( "Dollars=P Interest=I Rate of interest=r Time calculated in years=t. Simple interest formula is I=Prt.<BR>\n" );
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document.write( "Keeping this formula in mind and the information provided it would seem that 150=P x 0.04 x 2, next step looks like 150=P x 0.08, to get P we will divide 150 by 0.08. This works out to be 1875. So the principal is $1875.<BR>\n" );
document.write( "did i do this right?<BR>\n" );
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document.write( "Yes you did, and keep in mind that you can check your solution in the original eq:<BR>\n" );
document.write( "I = 1875 * .04 * 2<BR>\n" );
document.write( "I = 150 the given interest </SPAN>\n" );
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