document.write( "Question 8548: The problem I am working on is for some reason just escaping me. It is
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document.write( "15x-4=6x+3 \n" );
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Algebra.Com's Answer #4757 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! First, you must get all the x terms on one side. To get rid of the 6x on the right side, you can add -6x to each side:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15x - 4 = 6x + 3 \n" ); document.write( "15x -6x - 4 = 6x - 6x + 3 \n" ); document.write( "9x - 4 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, you need to get all the \"non-x\" terms on the OTHER side. In this case, it will be nice to get rid of the -4, so you add +4 to each side: \n" ); document.write( "9x - 4 = 3 \n" ); document.write( "9x -4 +4 = 3 + 4 \n" ); document.write( "9x = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The last step is to get the x by itself. To get rid of the 9, you must realize that the operation between the 9 and the x is multiplication, so you must undo multiplication--that is, divide both sides by 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It's ugly, but in math you just have to get used to ugly!! It happens all the time. Life doesn't always come out even!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |