document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=780423>Question 780423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A committee is to have four members. There are seven men and six women available to serve on the committee. How many different committees can be formed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475668 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A committee is to have four members. There are seven men and six women available to serve on the committee. How many different committees can be formed?<BR>\n" );
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document.write( "men/women<BR>\n" );
document.write( "0/4----- 6C4 = 6C2 = 15 ways<BR>\n" );
document.write( "1/3----- 7*6C3 = 7*20 = 140 ways<BR>\n" );
document.write( "2/2----- 7C2*6C2 = 21*15 = 315 ways<BR>\n" );
document.write( "3/1----- 7C3*6C1 = 210 ways<BR>\n" );
document.write( "4/0----- 7C4*1 = 35 ways<BR>\n" );
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document.write( "Total:: 15+140+315+210+35 = 715 ways<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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