document.write( "Question 780564: How do I write csc 2x in terms of csc x?
\n" ); document.write( "This is what i've done so far:
\n" ); document.write( "\"+csc%282x%29+=+csc+%28x%29%2F2+sqrt%28+1-%281%2Fcsc%28x%29%5E%282%29%29+%29+\"
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Algebra.Com's Answer #475643 by Alan3354(69443)\"\" \"About 
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How do I write csc 2x in terms of csc x?
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\n" ); document.write( "csc(x) = 1/sin(x)
\n" ); document.write( "\"csc%282x%29+=+1%2F%282sin%28x%29%2Acos%28x%29%29\"
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