document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=780431>Question 780431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a triangle has one side of 10 cm and a second side of 20 cm and an included angle of 30 degrees, find the length of the third side.\r<BR>\n" );
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document.write( "I used law of cosines and came out with the answer of 199.1 cm..which doesn't seem porportional to the other 2 lengths.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #475589 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=475589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a triangle has one side of 10 cm and a second side of 20 cm and an included angle of 30 degrees, find the length of the third side.<BR>\n" );
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document.write( "199 is too long.<BR>\n" );
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document.write( "s^2 = 10^2 + 20^2 - 2*10*20*cos(30) = 500 - 400*sqrt(3)/2<BR>\n" );
document.write( "s =~ 12.393 cm<BR>\n" );
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